4h^2-26h-4=0

Solution for 4h^2-26h-4=0 equation:

4h^2-26h-4=0

a = 4; b = -26; c = -4;
Δ = b2-4ac
Δ = -262-4·4·(-4)
Δ = 740
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{740}=\sqrt{4*185}=\sqrt{4}*\sqrt{185}=2\sqrt{185}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{185}}{2*4}=\frac{26-2\sqrt{185}}{8}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{185}}{2*4}=\frac{26+2\sqrt{185}}{8}
$